If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2+6x+12x+8x=0
We add all the numbers together, and all the variables
9x^2+26x=0
a = 9; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·9·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*9}=\frac{-52}{18} =-2+8/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*9}=\frac{0}{18} =0 $
| 10j+–3j−–4=–3 | | X-(15x-5)=-(-3x+5 | | 3^(x)=2^(x+1) | | 5(4c-1)-8=18c+5 | | 15x-15=2x+6 | | 2x10=-3x | | 9x2+6x+12x+8=0 | | -5k+3=18 | | 6(x+3)=26 | | 3c-6=4c | | y^2+7y-120=0 | | -16=6+5x | | 24=3x^2+2x | | r^2-15r=-44 | | -3+3n=4 | | -11y=-7 | | 11x-5+9x-3=136 | | 80+x+95+38=160 | | 20−2z=10 | | (x+6)2-16=0 | | x+2x+4x=x | | 7x=3+5.5x | | 15x-40=3x-8 | | x+2x+4x=0 | | 17-4h=14-h | | 6x-19=(12x-5)-(2x+7) | | 8=26-3x | | -8x-2=4x+10 | | 8n+(-4)=28 | | 9(j−90)=81 | | 14x+2= 9x−3 | | 4x+14+3x=161 |